No, I understood that’s how it worked and I’m getting the desired result. The issue is that with certain ratios putting in the “wrong” value means that the other value is outside of the range allowed.
Of course I checked this message just as I’m off to work so I’ll follow up later with a concrete example.
Thank you so much for the reply!
- This reply was modified 2 years ago by jaberg. Reason: More accurate assessment